(16+2x)(22+2x)=832

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Solution for (16+2x)(22+2x)=832 equation:



(16+2x)(22+2x)=832
We move all terms to the left:
(16+2x)(22+2x)-(832)=0
We add all the numbers together, and all the variables
(2x+16)(2x+22)-832=0
We multiply parentheses ..
(+4x^2+44x+32x+352)-832=0
We get rid of parentheses
4x^2+44x+32x+352-832=0
We add all the numbers together, and all the variables
4x^2+76x-480=0
a = 4; b = 76; c = -480;
Δ = b2-4ac
Δ = 762-4·4·(-480)
Δ = 13456
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{13456}=116$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(76)-116}{2*4}=\frac{-192}{8} =-24 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(76)+116}{2*4}=\frac{40}{8} =5 $

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