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(16+2x)(8+2x)=1008
We move all terms to the left:
(16+2x)(8+2x)-(1008)=0
We add all the numbers together, and all the variables
(2x+16)(2x+8)-1008=0
We multiply parentheses ..
(+4x^2+16x+32x+128)-1008=0
We get rid of parentheses
4x^2+16x+32x+128-1008=0
We add all the numbers together, and all the variables
4x^2+48x-880=0
a = 4; b = 48; c = -880;
Δ = b2-4ac
Δ = 482-4·4·(-880)
Δ = 16384
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16384}=128$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-128}{2*4}=\frac{-176}{8} =-22 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+128}{2*4}=\frac{80}{8} =10 $
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