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(16+2x)(8+2x)=384
We move all terms to the left:
(16+2x)(8+2x)-(384)=0
We add all the numbers together, and all the variables
(2x+16)(2x+8)-384=0
We multiply parentheses ..
(+4x^2+16x+32x+128)-384=0
We get rid of parentheses
4x^2+16x+32x+128-384=0
We add all the numbers together, and all the variables
4x^2+48x-256=0
a = 4; b = 48; c = -256;
Δ = b2-4ac
Δ = 482-4·4·(-256)
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{6400}=80$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-80}{2*4}=\frac{-128}{8} =-16 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+80}{2*4}=\frac{32}{8} =4 $
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