(16-2x)/x=-x-10

Solution for (16-2x)/x=-x-10 equation:

(16-2x)/x=-x-10

We move all terms to the left:

(16-2x)/x-(-x-10)=0


Domain of the equation: x!=0

x∈R


We add all the numbers together, and all the variables

(-2x+16)/x-(-1x-10)=0

We get rid of parentheses

(-2x+16)/x+1x+10=0

We multiply all the terms by the denominator


(-2x+16)+1x*x+10*x=0

We add all the numbers together, and all the variables

10x+(-2x+16)+1x*x=0

Wy multiply elements

x^2+10x+(-2x+16)=0

We get rid of parentheses

x^2+10x-2x+16=0

We add all the numbers together, and all the variables

x^2+8x+16=0

a = 1; b = 8; c = +16;
Δ = b2-4ac
Δ = 82-4·1·16
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-8}{2}=-4$