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(16-3*5)q+13=(2*9-16)q+(3*4/12-1)
We move all terms to the left:
(16-3*5)q+13-((2*9-16)q+(3*4/12-1))=0
We add all the numbers together, and all the variables
1q-(2q+(3*4/12-1))+13=0
We add all the numbers together, and all the variables
q-(2q+(3*4/12-1))+13=0
We multiply all the terms by the denominator
q*12-1))-(2q+(3*4+13*12-1))=0
We add all the numbers together, and all the variables
q*12-1))-(2q+167)=0
Wy multiply elements
12q-1))-(2q+167)=0
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