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(16-x/3)=x
We move all terms to the left:
(16-x/3)-(x)=0
We add all the numbers together, and all the variables
(-x/3+16)-x=0
We add all the numbers together, and all the variables
-1x+(-x/3+16)=0
We get rid of parentheses
-1x-x/3+16=0
We multiply all the terms by the denominator
-1x*3-x+16*3=0
We add all the numbers together, and all the variables
-1x-1x*3+48=0
Wy multiply elements
-1x-3x+48=0
We add all the numbers together, and all the variables
-4x+48=0
We move all terms containing x to the left, all other terms to the right
-4x=-48
x=-48/-4
x=+12
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