(160+3x=195-2x)

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Solution for (160+3x=195-2x) equation: 



(160+3x=195-2x)

We move all terms to the left:

(160+3x-(195-2x))=0

We add all the numbers together, and all the variables

(160+3x-(-2x+195))=0



We calculate terms in parentheses: +(160+3x-(-2x+195)), so:

160+3x-(-2x+195)

determiningTheFunctionDomain
3x-(-2x+195)+160

We get rid of parentheses

3x+2x-195+160

We add all the numbers together, and all the variables

5x-35

Back to the equation:

+(5x-35)



We get rid of parentheses

5x-35=0

We move all terms containing x to the left, all other terms to the right

5x=35

x=35/5

x=7

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