(160-4x)+6x+5x=300

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Solution for (160-4x)+6x+5x=300 equation: 



(160-4x)+6x+5x=300

We move all terms to the left:

(160-4x)+6x+5x-(300)=0

We add all the numbers together, and all the variables

(-4x+160)+6x+5x-300=0

We add all the numbers together, and all the variables

11x+(-4x+160)-300=0

We get rid of parentheses

11x-4x+160-300=0

We add all the numbers together, and all the variables

7x-140=0

We move all terms containing x to the left, all other terms to the right

7x=140

x=140/7

x=20

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