(16b-4)-5(3b+3)=-7

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Solution for (16b-4)-5(3b+3)=-7 equation: 



(16b-4)-5(3b+3)=-7

We move all terms to the left:

(16b-4)-5(3b+3)-(-7)=0

We add all the numbers together, and all the variables

(16b-4)-5(3b+3)+7=0

We multiply parentheses

(16b-4)-15b-15+7=0

We get rid of parentheses

16b-15b-4-15+7=0

We add all the numbers together, and all the variables

b-12=0

We move all terms containing b to the left, all other terms to the right

b=12

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