(16b-4)-5(3b+3)=7

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Solution for (16b-4)-5(3b+3)=7 equation: 



(16b-4)-5(3b+3)=7

We move all terms to the left:

(16b-4)-5(3b+3)-(7)=0

We multiply parentheses

(16b-4)-15b-15-7=0

We get rid of parentheses

16b-15b-4-15-7=0

We add all the numbers together, and all the variables

b-26=0

We move all terms containing b to the left, all other terms to the right

b=26

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