(16i-28j)-(4i+8j)=

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Solution for (16i-28j)-(4i+8j)= equation:


Simplifying
(16i + -28j) + -1(4i + 8j) = 0

Remove parenthesis around (16i + -28j)
16i + -28j + -1(4i + 8j) = 0
16i + -28j + (4i * -1 + 8j * -1) = 0
16i + -28j + (-4i + -8j) = 0

Reorder the terms:
16i + -4i + -28j + -8j = 0

Combine like terms: 16i + -4i = 12i
12i + -28j + -8j = 0

Combine like terms: -28j + -8j = -36j
12i + -36j = 0

Solving
12i + -36j = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '36j' to each side of the equation.
12i + -36j + 36j = 0 + 36j

Combine like terms: -36j + 36j = 0
12i + 0 = 0 + 36j
12i = 0 + 36j
Remove the zero:
12i = 36j

Divide each side by '12'.
i = 3j

Simplifying
i = 3j

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