(16t)(7-t)=0

Solution for (16t)(7-t)=0 equation:

(16t)(7-t)=0

We add all the numbers together, and all the variables

16t(-1t+7)=0

We multiply parentheses

-16t^2+112t=0

a = -16; b = 112; c = 0;
Δ = b2-4ac
Δ = 1122-4·(-16)·0
Δ = 12544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{12544}=112$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(112)-112}{2*-16}=\frac{-224}{-32}
=+7
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(112)+112}{2*-16}=\frac{0}{-32}
=0
$