(16x)(8x+26)=134

Solution for (16x)(8x+26)=134 equation:

(16x)(8x+26)=134

We move all terms to the left:

(16x)(8x+26)-(134)=0

We multiply parentheses

128x^2+416x-134=0

a = 128; b = 416; c = -134;
Δ = b2-4ac
Δ = 4162-4·128·(-134)
Δ = 241664
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{241664}=\sqrt{4096*59}=\sqrt{4096}*\sqrt{59}=64\sqrt{59}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(416)-64\sqrt{59}}{2*128}=\frac{-416-64\sqrt{59}}{256}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(416)+64\sqrt{59}}{2*128}=\frac{-416+64\sqrt{59}}{256}
$