(16x+19)+(12x+3)=180

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Solution for (16x+19)+(12x+3)=180 equation: 



(16x+19)+(12x+3)=180

We move all terms to the left:

(16x+19)+(12x+3)-(180)=0

We get rid of parentheses

16x+12x+19+3-180=0

We add all the numbers together, and all the variables

28x-158=0

We move all terms containing x to the left, all other terms to the right

28x=158

x=158/28

x=5+9/14

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