(16x+4)+110+(3x+11)=180

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Solution for (16x+4)+110+(3x+11)=180 equation: 



(16x+4)+110+(3x+11)=180

We move all terms to the left:

(16x+4)+110+(3x+11)-(180)=0

We add all the numbers together, and all the variables

(16x+4)+(3x+11)-70=0

We get rid of parentheses

16x+3x+4+11-70=0

We add all the numbers together, and all the variables

19x-55=0

We move all terms containing x to the left, all other terms to the right

19x=55

x=55/19

x=2+17/19

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