(16x+4)+110=(3x+11)

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Solution for (16x+4)+110=(3x+11) equation: 



(16x+4)+110=(3x+11)

We move all terms to the left:

(16x+4)+110-((3x+11))=0

We get rid of parentheses

16x-((3x+11))+4+110=0



We calculate terms in parentheses: -((3x+11)), so:

(3x+11)

We get rid of parentheses

3x+11

Back to the equation:

-(3x+11)



We add all the numbers together, and all the variables

16x-(3x+11)+114=0

We get rid of parentheses

16x-3x-11+114=0

We add all the numbers together, and all the variables

13x+103=0

We move all terms containing x to the left, all other terms to the right

13x=-103

x=-103/13

x=-7+12/13

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