(16x+5)(16x-5)=5

Solution for (16x+5)(16x-5)=5 equation:

(16x+5)(16x-5)=5

We move all terms to the left:

(16x+5)(16x-5)-(5)=0

We use the square of the difference formula

256x^2-25-5=0

We add all the numbers together, and all the variables

256x^2-30=0

a = 256; b = 0; c = -30;
Δ = b2-4ac
Δ = 02-4·256·(-30)
Δ = 30720
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{30720}=\sqrt{1024*30}=\sqrt{1024}*\sqrt{30}=32\sqrt{30}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-32\sqrt{30}}{2*256}=\frac{0-32\sqrt{30}}{512}
=-\frac{32\sqrt{30}}{512}
=-\frac{\sqrt{30}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+32\sqrt{30}}{2*256}=\frac{0+32\sqrt{30}}{512}
=\frac{32\sqrt{30}}{512}
=\frac{\sqrt{30}}{16}
$