(16x+53)-(9-2x)+(4x+3)-(1x-45)=(45x+13)

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Solution for (16x+53)-(9-2x)+(4x+3)-(1x-45)=(45x+13) equation: 



(16x+53)-(9-2x)+(4x+3)-(1x-45)=(45x+13)

We move all terms to the left:

(16x+53)-(9-2x)+(4x+3)-(1x-45)-((45x+13))=0

We add all the numbers together, and all the variables

(16x+53)-(-2x+9)+(4x+3)-(x-45)-((45x+13))=0

We get rid of parentheses

16x+2x+4x-x-((45x+13))+53-9+3+45=0



We calculate terms in parentheses: -((45x+13)), so:

(45x+13)

We get rid of parentheses

45x+13

Back to the equation:

-(45x+13)



We add all the numbers together, and all the variables

21x-(45x+13)+92=0

We get rid of parentheses

21x-45x-13+92=0

We add all the numbers together, and all the variables

-24x+79=0

We move all terms containing x to the left, all other terms to the right

-24x=-79

x=-79/-24

x=3+7/24

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