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(16x-3)(9x+11)=128
We move all terms to the left:
(16x-3)(9x+11)-(128)=0
We multiply parentheses ..
(+144x^2+176x-27x-33)-128=0
We get rid of parentheses
144x^2+176x-27x-33-128=0
We add all the numbers together, and all the variables
144x^2+149x-161=0
a = 144; b = 149; c = -161;
Δ = b2-4ac
Δ = 1492-4·144·(-161)
Δ = 114937
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(149)-\sqrt{114937}}{2*144}=\frac{-149-\sqrt{114937}}{288} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(149)+\sqrt{114937}}{2*144}=\frac{-149+\sqrt{114937}}{288} $
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