(16x-3)=(12x+37)

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Solution for (16x-3)=(12x+37) equation: 



(16x-3)=(12x+37)

We move all terms to the left:

(16x-3)-((12x+37))=0

We get rid of parentheses

16x-((12x+37))-3=0



We calculate terms in parentheses: -((12x+37)), so:

(12x+37)

We get rid of parentheses

12x+37

Back to the equation:

-(12x+37)



We get rid of parentheses

16x-12x-37-3=0

We add all the numbers together, and all the variables

4x-40=0

We move all terms containing x to the left, all other terms to the right

4x=40

x=40/4

x=10

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