(16x-3)=(9x+11)

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Solution for (16x-3)=(9x+11) equation: 



(16x-3)=(9x+11)

We move all terms to the left:

(16x-3)-((9x+11))=0

We get rid of parentheses

16x-((9x+11))-3=0



We calculate terms in parentheses: -((9x+11)), so:

(9x+11)

We get rid of parentheses

9x+11

Back to the equation:

-(9x+11)



We get rid of parentheses

16x-9x-11-3=0

We add all the numbers together, and all the variables

7x-14=0

We move all terms containing x to the left, all other terms to the right

7x=14

x=14/7

x=2

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