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(16x-4)(6x+12)=180
We move all terms to the left:
(16x-4)(6x+12)-(180)=0
We multiply parentheses ..
(+96x^2+192x-24x-48)-180=0
We get rid of parentheses
96x^2+192x-24x-48-180=0
We add all the numbers together, and all the variables
96x^2+168x-228=0
a = 96; b = 168; c = -228;
Δ = b2-4ac
Δ = 1682-4·96·(-228)
Δ = 115776
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{115776}=\sqrt{576*201}=\sqrt{576}*\sqrt{201}=24\sqrt{201}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(168)-24\sqrt{201}}{2*96}=\frac{-168-24\sqrt{201}}{192} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(168)+24\sqrt{201}}{2*96}=\frac{-168+24\sqrt{201}}{192} $
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