(16x/12)=(7/8)

Solution for (16x/12)=(7/8) equation:

(16x/12)=(7/8)

We move all terms to the left:

(16x/12)-((7/8))=0

We add all the numbers together, and all the variables

(+16x/12)-((+7/8))=0

We get rid of parentheses

16x/12-((+7/8))=0

We calculate fractions


128x^2/()+()/()=0

We add all the numbers together, and all the variables

128x^2/()+1=0

We multiply all the terms by the denominator


128x^2+1*()=0

We add all the numbers together, and all the variables

128x^2=0

a = 128; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·128·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{256}=0$