(16y-1)(16-y)=0

Solution for (16y-1)(16-y)=0 equation:

(16y-1)(16-y)=0

We add all the numbers together, and all the variables

(16y-1)(-1y+16)=0

We multiply parentheses ..

(-16y^2+256y+y-16)=0

We get rid of parentheses

-16y^2+256y+y-16=0

We add all the numbers together, and all the variables

-16y^2+257y-16=0

a = -16; b = 257; c = -16;
Δ = b2-4ac
Δ = 2572-4·(-16)·(-16)
Δ = 65025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{65025}=255$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(257)-255}{2*-16}=\frac{-512}{-32}
=+16
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(257)+255}{2*-16}=\frac{-2}{-32}
=1/16
$