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(17+2x)(13+2x)=357
We move all terms to the left:
(17+2x)(13+2x)-(357)=0
We add all the numbers together, and all the variables
(2x+17)(2x+13)-357=0
We multiply parentheses ..
(+4x^2+26x+34x+221)-357=0
We get rid of parentheses
4x^2+26x+34x+221-357=0
We add all the numbers together, and all the variables
4x^2+60x-136=0
a = 4; b = 60; c = -136;
Δ = b2-4ac
Δ = 602-4·4·(-136)
Δ = 5776
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5776}=76$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-76}{2*4}=\frac{-136}{8} =-17 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+76}{2*4}=\frac{16}{8} =2 $
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