(17+2x)/(3x+1)=3/4

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Solution for (17+2x)/(3x+1)=3/4 equation: 


D( x )

3*x+1 = 0

3*x+1 = 0

3*x+1 = 0

3*x+1 = 0 // - 1

3*x = -1 // : 3

x = -1/3

x in (-oo:-1/3) U (-1/3:+oo)

(2*x+17)/(3*x+1) = 3/4 // - 3/4

(2*x+17)/(3*x+1)-(3/4) = 0

(2*x+17)/(3*x+1)-3/4 = 0

(4*(2*x+17))/(4*(3*x+1))+(-3*(3*x+1))/(4*(3*x+1)) = 0

4*(2*x+17)-3*(3*x+1) = 0

65-x = 0

(65-x)/(4*(3*x+1)) = 0

(65-x)/(4*(3*x+1)) = 0 // * 4*(3*x+1)

65-x = 0

65-x = 0 // - 65

-x = -65 // * -1

x = 65

x = 65

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