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(17+y)y=89
We move all terms to the left:
(17+y)y-(89)=0
We add all the numbers together, and all the variables
(y+17)y-89=0
We multiply parentheses
y^2+17y-89=0
a = 1; b = 17; c = -89;
Δ = b2-4ac
Δ = 172-4·1·(-89)
Δ = 645
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-\sqrt{645}}{2*1}=\frac{-17-\sqrt{645}}{2} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+\sqrt{645}}{2*1}=\frac{-17+\sqrt{645}}{2} $
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