(17-x)/2=(49+2x)/5+5

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Solution for (17-x)/2=(49+2x)/5+5 equation: 



(17-x)/2=(49+2x)/5+5

We move all terms to the left:

(17-x)/2-((49+2x)/5+5)=0

We add all the numbers together, and all the variables

(-1x+17)/2-((2x+49)/5+5)=0

We calculate fractions


(-5x+85)/()+(-((2x+49)*2)/()=0



We calculate terms in parentheses: +(-((2x+49)*2)/(), so:

-((2x+49)*2)/(

We multiply all the terms by the denominator


-((2x+49)*2)



We calculate terms in parentheses: -((2x+49)*2), so:

(2x+49)*2

We multiply parentheses

4x+98

Back to the equation:

-(4x+98)



We get rid of parentheses

-4x-98

Back to the equation:

+(-4x-98)



We get rid of parentheses

(-5x+85)/()-4x-98=0

We multiply all the terms by the denominator


(-5x+85)-4x*()-98*()=0

We add all the numbers together, and all the variables

(-5x+85)-4x*()=0

We get rid of parentheses

-5x-4x*()+85=0

We move all terms containing x to the left, all other terms to the right

-5x-4x*()=-85

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