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(17/3)x=34
We move all terms to the left:
(17/3)x-(34)=0
Domain of the equation: 3)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+17/3)x-34=0
We multiply parentheses
17x^2-34=0
a = 17; b = 0; c = -34;
Δ = b2-4ac
Δ = 02-4·17·(-34)
Δ = 2312
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2312}=\sqrt{1156*2}=\sqrt{1156}*\sqrt{2}=34\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-34\sqrt{2}}{2*17}=\frac{0-34\sqrt{2}}{34} =-\frac{34\sqrt{2}}{34} =-\sqrt{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+34\sqrt{2}}{2*17}=\frac{0+34\sqrt{2}}{34} =\frac{34\sqrt{2}}{34} =\sqrt{2} $
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