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(18+2x)(30+2x)=1120
We move all terms to the left:
(18+2x)(30+2x)-(1120)=0
We add all the numbers together, and all the variables
(2x+18)(2x+30)-1120=0
We multiply parentheses ..
(+4x^2+60x+36x+540)-1120=0
We get rid of parentheses
4x^2+60x+36x+540-1120=0
We add all the numbers together, and all the variables
4x^2+96x-580=0
a = 4; b = 96; c = -580;
Δ = b2-4ac
Δ = 962-4·4·(-580)
Δ = 18496
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{18496}=136$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(96)-136}{2*4}=\frac{-232}{8} =-29 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(96)+136}{2*4}=\frac{40}{8} =5 $
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