(18+2x)*(20+2x)=0

Solution for (18+2x)*(20+2x)=0 equation:

(18+2x)(20+2x)=0

We add all the numbers together, and all the variables

(2x+18)(2x+20)=0

We multiply parentheses ..

(+4x^2+40x+36x+360)=0

We get rid of parentheses

4x^2+40x+36x+360=0

We add all the numbers together, and all the variables

4x^2+76x+360=0

a = 4; b = 76; c = +360;
Δ = b2-4ac
Δ = 762-4·4·360
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(76)-4}{2*4}=\frac{-80}{8}
=-10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(76)+4}{2*4}=\frac{-72}{8}
=-9
$