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(18+3x)*x=120
We move all terms to the left:
(18+3x)*x-(120)=0
We add all the numbers together, and all the variables
(3x+18)*x-120=0
We multiply parentheses
3x^2+18x-120=0
a = 3; b = 18; c = -120;
Δ = b2-4ac
Δ = 182-4·3·(-120)
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1764}=42$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-42}{2*3}=\frac{-60}{6} =-10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+42}{2*3}=\frac{24}{6} =4 $
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