(18-2x)(25-2x)=294

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Solution for (18-2x)(25-2x)=294 equation:



(18-2x)(25-2x)=294
We move all terms to the left:
(18-2x)(25-2x)-(294)=0
We add all the numbers together, and all the variables
(-2x+18)(-2x+25)-294=0
We multiply parentheses ..
(+4x^2-50x-36x+450)-294=0
We get rid of parentheses
4x^2-50x-36x+450-294=0
We add all the numbers together, and all the variables
4x^2-86x+156=0
a = 4; b = -86; c = +156;
Δ = b2-4ac
Δ = -862-4·4·156
Δ = 4900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4900}=70$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-86)-70}{2*4}=\frac{16}{8} =2 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-86)+70}{2*4}=\frac{156}{8} =19+1/2 $

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