(18-4x)+18*2(x+2)+12(x+2)+24x=380

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Solution for (18-4x)+18*2(x+2)+12(x+2)+24x=380 equation: 



(18-4x)+18*2(x+2)+12(x+2)+24x=380

We move all terms to the left:

(18-4x)+18*2(x+2)+12(x+2)+24x-(380)=0

We add all the numbers together, and all the variables

(-4x+18)+18*2(x+2)+12(x+2)+24x-380=0

We add all the numbers together, and all the variables

24x+(-4x+18)+18*2(x+2)+12(x+2)-380=0

We multiply parentheses

24x+(-4x+18)+18*2(x+2)+12x+24-380=0

Wy multiply elements

24x+(-4x+18)+36x(x+12x+24-380=0

We get rid of parentheses

24x-4x+36x(x+12x+24-380+18=0

We add all the numbers together, and all the variables

20x+36x(x+12x+24-380+18=0

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