(18-5x)/(3x+2)=7/3

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Solution for (18-5x)/(3x+2)=7/3 equation: 



(18-5x)/(3x+2)=7/3

We move all terms to the left:

(18-5x)/(3x+2)-(7/3)=0



Domain of the equation: (3x+2)!=0

We move all terms containing x to the left, all other terms to the right

3x!=-2

x!=-2/3

x!=-2/3

x∈R



We add all the numbers together, and all the variables

(-5x+18)/(3x+2)-(+7/3)=0

We get rid of parentheses

(-5x+18)/(3x+2)-7/3=0

We calculate fractions


(-15x+54)/(9x+6)+(-21x-14)/(9x+6)=0

We multiply all the terms by the denominator


(-15x+54)+(-21x-14)=0

We get rid of parentheses

-15x-21x+54-14=0

We add all the numbers together, and all the variables

-36x+40=0

We move all terms containing x to the left, all other terms to the right

-36x=-40

x=-40/-36

x=1+1/9

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