(18-6)+(36+4x)=12-(4x-18)

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Solution for (18-6)+(36+4x)=12-(4x-18) equation: 



(18-6)+(36+4x)=12-(4x-18)

We move all terms to the left:

(18-6)+(36+4x)-(12-(4x-18))=0

We add all the numbers together, and all the variables

(4x+36)-(12-(4x-18))+12=0

We get rid of parentheses

4x-(12-(4x-18))+36+12=0



We calculate terms in parentheses: -(12-(4x-18)), so:

12-(4x-18)

determiningTheFunctionDomain
-(4x-18)+12

We get rid of parentheses

-4x+18+12

We add all the numbers together, and all the variables

-4x+30

Back to the equation:

-(-4x+30)



We add all the numbers together, and all the variables

4x-(-4x+30)+48=0

We get rid of parentheses

4x+4x-30+48=0

We add all the numbers together, and all the variables

8x+18=0

We move all terms containing x to the left, all other terms to the right

8x=-18

x=-18/8

x=-2+1/4

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