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(18/7)x=6
We move all terms to the left:
(18/7)x-(6)=0
Domain of the equation: 7)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+18/7)x-6=0
We multiply parentheses
18x^2-6=0
a = 18; b = 0; c = -6;
Δ = b2-4ac
Δ = 02-4·18·(-6)
Δ = 432
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{432}=\sqrt{144*3}=\sqrt{144}*\sqrt{3}=12\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{3}}{2*18}=\frac{0-12\sqrt{3}}{36} =-\frac{12\sqrt{3}}{36} =-\frac{\sqrt{3}}{3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{3}}{2*18}=\frac{0+12\sqrt{3}}{36} =\frac{12\sqrt{3}}{36} =\frac{\sqrt{3}}{3} $
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