(180-(3x+4))+(6x+1)+(x-21)=180

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Solution for (180-(3x+4))+(6x+1)+(x-21)=180 equation: 



(180-(3x+4))+(6x+1)+(x-21)=180

We move all terms to the left:

(180-(3x+4))+(6x+1)+(x-21)-(180)=0

We get rid of parentheses

(180-(3x+4))+6x+x+1-21-180=0



We calculate terms in parentheses: +(180-(3x+4)), so:

180-(3x+4)

determiningTheFunctionDomain
-(3x+4)+180

We get rid of parentheses

-3x-4+180

We add all the numbers together, and all the variables

-3x+176

Back to the equation:

+(-3x+176)



We add all the numbers together, and all the variables

7x+(-3x+176)-200=0

We get rid of parentheses

7x-3x+176-200=0

We add all the numbers together, and all the variables

4x-24=0

We move all terms containing x to the left, all other terms to the right

4x=24

x=24/4

x=6

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