(180-(9x+16))+((6x+4)+(4x-2))=180

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Solution for (180-(9x+16))+((6x+4)+(4x-2))=180 equation: 



(180-(9x+16))+((6x+4)+(4x-2))=180

We move all terms to the left:

(180-(9x+16))+((6x+4)+(4x-2))-(180)=0



We calculate terms in parentheses: +(180-(9x+16)), so:

180-(9x+16)

determiningTheFunctionDomain
-(9x+16)+180

We get rid of parentheses

-9x-16+180

We add all the numbers together, and all the variables

-9x+164

Back to the equation:

+(-9x+164)





We calculate terms in parentheses: +((6x+4)+(4x-2)), so:

(6x+4)+(4x-2)

We get rid of parentheses

6x+4x+4-2

We add all the numbers together, and all the variables

10x+2

Back to the equation:

+(10x+2)



We get rid of parentheses

-9x+10x+164+2-180=0

We add all the numbers together, and all the variables

x-14=0

We move all terms containing x to the left, all other terms to the right

x=14

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