(180-4x)+(160-4x)+(160-3x)=180

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Solution for (180-4x)+(160-4x)+(160-3x)=180 equation: 



(180-4x)+(160-4x)+(160-3x)=180

We move all terms to the left:

(180-4x)+(160-4x)+(160-3x)-(180)=0

We add all the numbers together, and all the variables

(-4x+180)+(-4x+160)+(-3x+160)-180=0

We get rid of parentheses

-4x-4x-3x+180+160+160-180=0

We add all the numbers together, and all the variables

-11x+320=0

We move all terms containing x to the left, all other terms to the right

-11x=-320

x=-320/-11

x=29+1/11

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