(18x)(-9x)=(-35)

Solution for (18x)(-9x)=(-35) equation:

(18x)(-9x)=(-35)

We move all terms to the left:

(18x)(-9x)-((-35))=0

We add all the numbers together, and all the variables

18x(-9x)+35=0

We multiply parentheses

-162x^2+35=0

a = -162; b = 0; c = +35;
Δ = b2-4ac
Δ = 02-4·(-162)·35
Δ = 22680
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{22680}=\sqrt{324*70}=\sqrt{324}*\sqrt{70}=18\sqrt{70}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-18\sqrt{70}}{2*-162}=\frac{0-18\sqrt{70}}{-324}
=-\frac{18\sqrt{70}}{-324}
=-\frac{\sqrt{70}}{-18}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+18\sqrt{70}}{2*-162}=\frac{0+18\sqrt{70}}{-324}
=\frac{18\sqrt{70}}{-324}
=\frac{\sqrt{70}}{-18}
$