(18y-12)=(9y+33)

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Solution for (18y-12)=(9y+33) equation: 



(18y-12)=(9y+33)

We move all terms to the left:

(18y-12)-((9y+33))=0

We get rid of parentheses

18y-((9y+33))-12=0



We calculate terms in parentheses: -((9y+33)), so:

(9y+33)

We get rid of parentheses

9y+33

Back to the equation:

-(9y+33)



We get rid of parentheses

18y-9y-33-12=0

We add all the numbers together, and all the variables

9y-45=0

We move all terms containing y to the left, all other terms to the right

9y=45

y=45/9

y=5

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