(19+(6x+2))/5=x

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Solution for (19+(6x+2))/5=x equation:



(19+(6x+2))/5=x
We move all terms to the left:
(19+(6x+2))/5-(x)=0
We add all the numbers together, and all the variables
-1x+(19+(6x+2))/5=0
We multiply all the terms by the denominator
-1x*5+(19+(6x+2))=0
We calculate terms in parentheses: +(19+(6x+2)), so:
19+(6x+2)
determiningTheFunctionDomain (6x+2)+19
We get rid of parentheses
6x+2+19
We add all the numbers together, and all the variables
6x+21
Back to the equation:
+(6x+21)
Wy multiply elements
-5x+(6x+21)=0
We get rid of parentheses
-5x+6x+21=0
We add all the numbers together, and all the variables
x+21=0
We move all terms containing x to the left, all other terms to the right
x=-21

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