(19-2(3x-1))/5=x+2

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Solution for (19-2(3x-1))/5=x+2 equation: 


x in (-oo:+oo)

(19-(2*(3*x-1)))/5 = x+2 // - x+2

(19-(2*(3*x-1)))/5-x-2 = 0

(19-2*(3*x-1))/5-x-2 = 0

(19-2*(3*x-1))/5+(5*(-x))/5+(-2*5)/5 = 0

5*(-x)-2*(3*x-1)-2*5+19 = 0

21-6*x-5*x-10 = 0

21-11*x-10 = 0

11-11*x = 0

(11-11*x)/5 = 0

(11-11*x)/5 = 0 // * 5

11-11*x = 0

11-11*x = 0 // - 11

-11*x = -11 // : -11

x = -11/(-11)

x = 1

x = 1

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