(19-2(3x-1))/5=x-2

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Solution for (19-2(3x-1))/5=x-2 equation: 



(19-2(3x-1))/5=x-2

We move all terms to the left:

(19-2(3x-1))/5-(x-2)=0

We get rid of parentheses

(19-2(3x-1))/5-x+2=0

We multiply all the terms by the denominator


(19-2(3x-1))-x*5+2*5=0



We calculate terms in parentheses: +(19-2(3x-1)), so:

19-2(3x-1)

determiningTheFunctionDomain
-2(3x-1)+19

We multiply parentheses

-6x+2+19

We add all the numbers together, and all the variables

-6x+21

Back to the equation:

+(-6x+21)



We add all the numbers together, and all the variables

(-6x+21)-x*5+10=0

Wy multiply elements

(-6x+21)-5x+10=0

We get rid of parentheses

-6x-5x+21+10=0

We add all the numbers together, and all the variables

-11x+31=0

We move all terms containing x to the left, all other terms to the right

-11x=-31

x=-31/-11

x=2+9/11

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