(19-2x)(35-2x)=0

Solution for (19-2x)(35-2x)=0 equation:

(19-2x)(35-2x)=0

We add all the numbers together, and all the variables

(-2x+19)(-2x+35)=0

We multiply parentheses ..

(+4x^2-70x-38x+665)=0

We get rid of parentheses

4x^2-70x-38x+665=0

We add all the numbers together, and all the variables

4x^2-108x+665=0

a = 4; b = -108; c = +665;
Δ = b2-4ac
Δ = -1082-4·4·665
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-108)-32}{2*4}=\frac{76}{8}
=9+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-108)+32}{2*4}=\frac{140}{8}
=17+1/2
$