(19-6x+2)/5=x+2

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Solution for (19-6x+2)/5=x+2 equation: 



(19-6x+2)/5=x+2

We move all terms to the left:

(19-6x+2)/5-(x+2)=0

We add all the numbers together, and all the variables

(-6x+21)/5-(x+2)=0

We get rid of parentheses

(-6x+21)/5-x-2=0

We multiply all the terms by the denominator


(-6x+21)-x*5-2*5=0

We add all the numbers together, and all the variables

(-6x+21)-x*5-10=0

Wy multiply elements

(-6x+21)-5x-10=0

We get rid of parentheses

-6x-5x+21-10=0

We add all the numbers together, and all the variables

-11x+11=0

We move all terms containing x to the left, all other terms to the right

-11x=-11

x=-11/-11

x=1

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