(19-x)(19-x)=0

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Solution for (19-x)(19-x)=0 equation:



(19-x)(19-x)=0
We add all the numbers together, and all the variables
(-1x+19)(-1x+19)=0
We multiply parentheses ..
(+x^2-19x-19x+361)=0
We get rid of parentheses
x^2-19x-19x+361=0
We add all the numbers together, and all the variables
x^2-38x+361=0
a = 1; b = -38; c = +361;
Δ = b2-4ac
Δ = -382-4·1·361
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{38}{2}=19$

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