(19/(6x+24))-(3/(x+4))

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Solution for (19/(6x+24))-(3/(x+4)) equation: 


D( x )

x+4 = 0

6*x+24 = 0

x+4 = 0

x+4 = 0

x+4 = 0 // - 4

x = -4

6*x+24 = 0

6*x+24 = 0

6*x+24 = 0 // - 24

6*x = -24 // : 6

x = -24/6

x = -4

x in (-oo:-4) U (-4:+oo)

19/(6*x+24)-(3/(x+4)) = 0

19/(6*x+24)-3*(x+4)^-1 = 0

19/(6*x+24)-3/(x+4) = 0

(19*(x+4))/((6*x+24)*(x+4))+(-3*(6*x+24))/((6*x+24)*(x+4)) = 0

19*(x+4)-3*(6*x+24) = 0

x+4 = 0

(x+4)/((6*x+24)*(x+4)) = 0

(x+4)/((6*x+24)*(x+4)) = 0 // * (6*x+24)*(x+4)

x+4 = 0

x+4 = 0 // - 4

x = -4

x in { -4} 

x belongs to the empty set

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