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(19/4)-3(1/2)a=-(1/4)a=(3/2)
We move all terms to the left:
(19/4)-3(1/2)a-(-(1/4)a)=0
Domain of the equation: 2)a!=0
a!=0/1
a!=0
a∈R
Domain of the equation: 4)a)!=0We add all the numbers together, and all the variables
a!=0/1
a!=0
a∈R
-3(+1/2)a-(-(+1/4)a)+(+19/4)=0
We multiply parentheses
-3a^2-(-(+1/4)a)+(+19/4)=0
We get rid of parentheses
-3a^2-(-(+1/4)a)+19/4=0
We calculate fractions
-3a^2=0
a = -3; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-3)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$a=\frac{-b}{2a}=\frac{0}{-6}=0$
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